Which equation represents a circle with the same radius as the circle shown but with a center at (-1, 1)? (x – 1)2 + (y + 1)2 = 16 (x – 1)2 + (y + 1)2 = 4 (x + 1)2 + (y –1)2 = 4 (x + 1)2 + (y – 1)2 = 16

Answer: Last option: [tex](x+1)^2+(y-1)^2=16[/tex]Step-by-step explanation: The missing figure is attached. The center-radius form of the circle equation is:  [tex](x - h)^2 + (y-k)^2 = r^2[/tex] Where the center of the circle is at the poitn [tex](h,k)[/tex]  and "r" is the radius. You can identify from the figure attached that the radius of the circle shown is 4 units. Since the other circle has the same radius and its center is at the point [tex](-1, 1)[/tex]; you can identify that: [tex]h=-1\\k=1\\r=4[/tex] Therefore, substituting values into [tex](x - h)^2 + (y-k)^2 = r^2[/tex], you get that the equation of that circle is: [tex](x - (-1))^2 + (y-1)^2 = 4^2\\\\(x+1)^2+(y-1)^2=16[/tex]