Solve the following system. Please show me how you did it.

Answer:x = 3, y = 4 and z = -5.Step-by-step explanation:Use the elimination method:-3x + 2y + z = -6...........(1)x + 3y + 2z = 5..............(2)4x + 4y + 3z = 13..........(3)Multiply the first equation by -2:6x - 4y - 2z = 12   Add this to equation (2):7x  - y  = 17...........(4)Now Multiply equation (2) by 3 and equation (3) by -23x + 9y + 6z = 15 ............(5)-8x - 8y - 6z = -26............(6)   Adding (5) + (6):-5x + y = -11..........(7)Now Add (7) and (4):2x = 6x = 3.Now  substitute for x in (4):7(3) - y = 17-y = 17 - 21 = -4y = 4.Finally substitute for x and y in equation (3) to find z:4(3) + 4(4)  +3z = 133z = 13 - 12 - 16 = -15z = -5.